Question 27 - Problems - Chapter 2¶
Problem:¶
Consider the automobile with the position as a function of time plotted in Fig. 2.5 (below).
The car stopped after 272m.

Question:¶
a) What is the average velocity for the interval from t=0 to t=10.0 s?
b) From t=10.0 s to t=14.3 s?
Solution:¶
$\bigtriangleup t_1 = 10.0 - 0 = 10.0s$
$\bigtriangleup t_2= 14.3 - 10.0 = 4.3s$
The traveled way $\bigtriangleup s_1 = 200m-0m=200m$
The traveled way $\bigtriangleup s_2 = 272m-200m=72m$
The average velocity:
$$
\overline v=\frac{\bigtriangleup s}{\bigtriangleup t}
$$